User:Teloss/Sandbox

Logarithm Math Project
Solve for x:
 * $$ 4^x - \log(5) = \log(20) $$
 * $$ x = \log_3(3)+ \log_3(9) $$
 * $$ \log(2^x) = \log(5) - \log(10^x) $$
 * $$ \log(2^{-x}) - \log(2^{-1}) = \log(7^{-1}) + \log(4^{-1}) $$
 * $$ 2\log(x) = \log(16) $$
 * $$ \log(x) - 2\log(5) = \log(2) $$
 * $$ 2^x = 27 $$
 * $$ 5^{x-2} = 4 $$
 * $$ x\log(50) = \log(25) + \log(2) $$
 * $$ A = Pe^{rt} $$


 * $$ \log_b(x) = \frac{\log_k(x)}{\log_k(b)} $$