User:Tevildo/sandbox

To express it as a general equation: $$ {V_l} = {{p V_g m_o} \over {R T \rho}} $$, where Vl is the volume of the liquid (in litres), p is the pressure of the gas (in atm), Vg is the volume of the tank (in litres), mo is the molar mass of the gas (in g/mol), R is the universal gas constant (in L·atm·mol−1·K−1), T is the temperature of the gas (in Kelvin), and ρ is the density of the liquid (in g/L). Putting in our numbers: $$ {V_l} = {{200 * 2.4 * 32} \over {0.08206 * 298 * 1141}} = {15360 \over 27901} = 0.5505 L$$. Tevildo (talk) 14:33, 8 November 2014 (UTC)