User:U Han Zin

Given:Any triangleABC. Prove:a²+b²=c²+2(h²±de);d≥/≤c or/and e≥/≤c. proof:a²=h²+d² (by pythagorous) b²=h²+e² (        too         ) a²+b²=2h²+d²+e² =2h²+d²-/+2de+e²±2de =2h²+(d-/+e)²±2de =c²+2(h²±de);d≥/≤c or/and e≥/≤c.