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Unit testing
17,500 mi/h 17,500 mi/h 17,500 mi/h 7.8232 km/s

72536 lb/ft2 72,536 lb/ft2 72536 lb/ft2 72536 lb/ft2 72536 lb/ft2 72536 lb/ft2 72536 lb/ft2 72536 lb/ft2

72,536 lbs/ft(2)

Date sort testing
'22, 12h

'22, 12h ', 12h '22, 12h '22, 12h '22, 12h

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Kinematic viscosity
In fluid dynamics, it is sometimes more appropriate to work in terms of kinematic viscosity (sometimes also called the momentum diffusivity), defined as the ratio of the dynamic viscosity ($μ$) over the density of the fluid ($ρ$). It is usually denoted by the Greek letter nu ($ν$):


 * $$\nu = \frac{\mu} {\rho},$$

$$\nu = \frac{\mu} {\rho},$$

and has the dimensions [ $\mathrm{(length)^2/time}$ ], therefore resulting in the SI units and the derived units:



\left[ \ \nu \ \right] = \frac {\rm m^2} {\rm s} = \mathrm {\frac {\rm N \cdot m} {\rm kg} \cdot s} = \mathrm {\frac {\rm J} {\rm kg} \cdot s} = \ [ \ $$ specific energy $$\ ] \ \times \ [\ $$ time $$\ ]$$.

Testing


\left[ \ \nu \ \right] = \frac {\rm m^2} {\rm s} = \mathrm {\frac {\rm N \cdot m} {\rm kg} \cdot s} = \mathrm {\frac {\rm J} {\rm kg} \cdot s} = \ [ $$ specific energy $$ ] \ \times \  [ $$ time $$\ ]$$.



\left[ \nu \right] = \frac {\rm m^2} {\rm s} = \mathrm {\frac {\rm N \cdot m} {\rm kg} \cdot s} = \mathrm {\frac {\rm J} {\rm kg} \cdot s} = \ [ $$ specific energy $$ ] \ \times \  [ $$ time$$ ]$$.


 * $$ \begin{align}

\left[ \nu \right] & = \frac {\rm m^2} {\rm s} \\ & = \mathrm {\frac {\rm N \cdot m} {\rm kg} \cdot s} \\ \end{align}$$


 * $$ \begin{align}

\left[ \nu \right] & = \frac {\rm m^2} {\rm s}  = \mathrm {\frac {\rm N \cdot m} {\rm kg} \cdot s} \\ && = \mathrm {\frac {\rm J} {\rm kg} \cdot s} \\ & = \ [\end{align}$$ specific energy $$]\ \times \ [$$ time$$]$$.

Conversion
1 - 3 ft 1000 kg  1000 kg  1000 kg  1000 kg  1000 kg  1 lb  1 lb  1000 N  1000 N

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test1 test

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