User talk:129.69.39.49

Are you certain this is a mistake? If U∩V=ø, then pos(U∩V)=0, but not necessarily pos(U)=0 or pos(V)=0

Hey, so I thought about this a little more. I think it should be   pos(U∩V) ≤ max( pos(U), pos(V) ). This is certainly true and I do not believe you can show much more. The converse, pos(U∩V) ≥ min( pos(U), pos(V) ) is certainly wrong if you consider Ω = {1,2} with possibility distribution pos({1}) = 1, pos({2}) = 1/2 and the events U = {1}, V = {2}, then pos(U) = 1, pos(V) = 1/2 but pos(U∩V) = pos(ø) = 0 ≤ 1/2 = min( pos(U), pos(V) ). What's your opinion? DrKrawabbel (talk) 09:34, 4 January 2019 (UTC)