User talk:152.22.37.23

$$\sum_{n=1}^\infty \frac{1}{n^2}=\frac{\pi^2}{6}$$

September 2020
Hello, I'm LizardJr8. I wanted to let you know that one or more of your recent contributions&#32;to Pedro Álvares Cabral have been undone because they did not appear constructive. If you would like to experiment, please use the sandbox. If you have any questions, you can ask for assistance at the Teahouse. Thanks. LizardJr8 (talk) 15:28, 29 September 2020 (UTC)
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hi
152.22.37.23 (talk) 01:24, 22 March 2021 (UTC)


 * 152.22.37.23 (talk) 01:29, 22 March 2021 (UTC)
 * 152.22.37.23 (talk) 01:40, 22 March 2021 (UTC)
 * 152.22.37.23 (talk) 15:33, 22 March 2021 (UTC)