User talk:AntiochCollege

Theory of Gravity
I have been working on a theory of gravity, and would like help modeling everything else that we know about gravity into the theory. So I can self publish my work in a journal or on a website like Wikipedia. Gravity is represented as F= G( (m1*m2) / r^2 ), and I would like to change this theory, but make sure that the math still works exactly the same. The Force Of Gravity is equal to the Gravitiational Constant multiplide by the masses of two objects, and divided by their distance  appart.

So in my game where you form a circle of 10 pennies that represent the gravitational pull of one object, and my individual penny which sits outside of the circle entirely solitary. The odds still remain 10/11, when you are flipping a fair coin to decide which pile wins each round. As the piles move there is a .09765625% of flipping 10 wins in a row for the individual penny, and a 50% chance that the pile of 10 pennies will win on the first round. But my question was, how do I calculate the average number of coin flips before the larger pile wins.

And the answer is k(n-k)

That's right, k(n-k). So in my illistration, you can see that the circle of 10 pennies attracts to lonely penny into its gravitational field after 10 coin flips on average. But theoretically the number of rounds in the game could come close to infinity. And in practice you win after the first round or too. And I think you can see how this example illistrates a basic understanding of gravity. If we assume that gravity accelerates everything on earth at 9.8 m/s^2. For example if we look at the earth as being a mass of 10 pennies, and we look as the signle penny as being a distance of 4.9 meters, then if we follow  this equation.

t = sqrt( ( 2(4.9 m) ) / ( 9.8 m/s^2 ) ) = 1 s

And if we say the average number of coin flips it takes to produce this effect is 10, then each coin flip represents 1/10th of a second. So on average it takes just 1 second. Now obviously with correct preportions of pennies, and more sophisticated mathematics, and a better understanding of the physical formulas for gravity. We could do a lot more. And be far more precise.

So here is my way of doing that. We are using the quadratic formula to solve: (2*n) / 9.8 = k(n-k), for k

k=(1/14) (7n +- sqrt(49 n^2 - 40 n)).

So now an example...

We are dropping a ball from 10 meters above the ground. So we plug 10 meters into n to solve for k.

k=(1/14) (7n +- sqrt(49 n^2 - 40 n)) k=9.791574237

To calculate the average number of coin flips in my game k(n-k), so we plug in k & n:

k*(10-k) = 2.040816327 = average number of coin flips

Now we take the square root of the average number of flips to get the actual time it takes to land:

sqrt(avg flips) = 1.428571429 = number of seconds to land.

Now finally to factor in a problem with my equation we say that if k is 9.791574327, that means our large gravity pile is that many pennies. And our small gravity pile is exactly 0.208425673 pennies!

15 Sept 2006 Edit to James Randi and Other Articles
Your edit to James Randi looks like vandalism. You provided no reasonable rationale for your action. "Usenet kookery that made it to Wikipedia" is not a verified (or verifiable) complaint. Please do not add nonsense to Wikipedia; it is considered vandalism. If you would like to experiment, use the sandbox. Thank you. —Wookipedian 05:32, 15 September 2006 (UTC)

Furthermore, you seem to have vandalized other articles as well. This includes Deletion policy, No original research, Stephen Colbert, Schizophrenia, Talk:Elephant/Colbert, etc. Your comments on some of these pages acknowledge that you are conducting extensive and deliberate vandalism. Please stop. Welcome to Wikipedia. We invite everyone to contribute constructively to our encyclopedia. Take a look at the welcome page if you would like to learn more about contributing. However, unconstructive edits are considered vandalism, and if you continue in this manner you may be blocked from editing without further warning. Please stop, and consider improving rather than damaging the work of others. Thank you. —Wookipedian 05:40, 15 September 2006 (UTC)