User talk:Aquazone

$$(148,\frac{5539}{21})$$ $$Yes\ (295,\frac{547}{84})$$ $$Possibly\ (294,10)$$ $$y=-\frac{1}{84}x^2+\frac{74}{21}x+3$$ $$x=\frac{-\frac{74}{21}-\sqrt{\frac{5539}{441}}}{-\frac{1}{42}}$$