User talk:Blgames

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Hi! I thought that these links might be helpful for you.

--Guy Macon (talk) 19:25, 21 April 2020 (UTC)


 * What is clear is that math proved Wikipedia as a place (in some way decimal, because it is digital) for lies, my report on https://en.wikipedia.org/wiki/Floating-point_arithmetic is still true, even after it has been removed... Use your pocket calculator because in the heading section of the page I am editing it says: "Encyclopedic content must be verifiable". The subject I pointed out is serious, because at the moment Math is not an exact science on every digital electronic system (I bet even for super calculators). Once upon a time there was a big nation called the United States of America (I was a fan of You), work to make it big again.

Luigi Baglio 20:33, 21 April 2020 (UTC)


 * You might want to click on the link WP:V and read the words


 * "On Wikipedia, verifiability means other people using the encyclopedia can check that the information comes from a reliable source. Wikipedia does not publish original research. Its content is determined by previously published information rather than the beliefs or experiences of editors. Even if you're sure something is true, it must be verifiable before you can add it."


 * Again I say, read WP:V and WP:OR. Following Wikipedia's policies is not optional..


 * In addition, you inserted a claim that appears to be factually incorrect. In this edit you made the following claim:


 * "Example, in any computing system the division $$\tfrac{1}{199} = 0,005025125628140703$$ which is not true, because $$\tfrac{1}{199} = 0,00525125628140703$$. The difference? $$0,00\underline{50}25125628140703 \text{ (wrong)} \not\equiv 0,00525125628140703$$"
 * Your math is wrong.
 * You can go to [ https://www.wolframalpha.com/input/?i=1%2F199 ] and see the correct answer:

0.005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201   005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201    005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201    005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201...
 * ...and the 99 digits of the above repeating decimal repeat forever.
 * Or you can go to [ http://petr.lastovicka.sweb.cz/others.html#pi ] and download a calculator that gives you the correct answer to as many decimal places as you want:

0.005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201   005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201    005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201    005025125628140703517587939698492462311557788944723618090452261306532663316582914572864321608040201...
 * ...and again the last 99 digits repeat forever.
 * Even the standard calculator that comes with Windows 10 gives you an answer that is correct to 32 places:

0.00502512562814070351758793969849‬
 * Now you know why we have policies like WP:V and WP:OR. They exist to keep incorrect information from being added to Wikipedia articles. And the main way we do that is insisting that any claim, including the extraordinary claim that every calculator and programming language gives an incorrect answer to a simple division problem, be backed up by a citation to a reliable secondary source. See WP:RS.


 * If, as you claim, you have written a program that says that 1 divided by 199 is 0,005251256... instead of 0,0050251256..., I would be willing to review your code and tell you why it is giving you that wrong answer. -Guy Macon (talk) 05:54, 22 April 2020 (UTC)


 * Hi, first to show you the source code, I appreciate your reply, and after 24 hours I have a suggestion for people like you that moderate on Wikipedia: Instead to remove people additions, you should drive these people where their contents can be published, Wikipedia is big, so if that page seems improper, tell people where and what they can do to get the ideas they exspressed not just on Wikipedia, but on the Internet in general.


 * Now let's talk about the division subject, this is the pure math to make the division (source code follows those same steps):


 * $$\tfrac{1}{199} = 0,\text{ }0\text{ }0\text{ }5\text{ }251\text{ }25628\text{ }140703$$


 * $$199$$ in $$1\text{?}$$ $$0$$ times, $$199$$ remainder $$\rightarrow 0,$$


 * $$\tfrac{1}{10} \times x = (\tfrac{199}{199} = 1)$$ the numerator is the remainder
 * $$x = \tfrac{1}{\tfrac{1}{10}} = 1 \times 10 = 10$$... The dividend is inherited so: $$\tfrac{10}{199}$$
 * $$199$$ in $$10\text{?}$$ $$0$$ times, $$199$$ remainder $$\rightarrow 0$$


 * $$\tfrac{1}{100} \times x = (\tfrac{199}{199} = 1)$$
 * $$x = \tfrac{1}{\tfrac{1}{100}} = 1 \times 100 = 100$$... The dividend is inherited again so: $$\tfrac{100}{199}$$
 * $$199$$ in $$100\text{?}$$ $$0$$ times, $$199$$ remainder $$\rightarrow 0$$


 * $$\tfrac{1}{1000} \times x = (\tfrac{199}{199} = 1)$$
 * $$x = \tfrac{1}{\tfrac{1}{1000}} = 1 \times 1000 = 1000$$... The dividend is inherited one more time so: $$\tfrac{1000}{199}$$
 * $$199$$ in $$1000\text{?}$$ $$\underline{5}$$ times, $$(1000 - 995) = 5$$ remainder $$\rightarrow 5$$


 * $$\tfrac{1}{10000} \times x = \tfrac{5}{199}$$
 * $$x = \tfrac{\tfrac{5}{199}}{\tfrac{1}{10000}} = \tfrac{5}{199} \times \tfrac{10000}{1} = \tfrac{(5 \times 10000)}{199} = \tfrac{50000}{199}$$
 * $$199$$ in $$50000\text{?}$$ $$251$$ times, $$\text{(50000 - 49949) =‬51}$$ remainder $$\rightarrow 251$$


 * $$\tfrac{1}{100000} \times x = \tfrac{51}{199}$$
 * $x = \tfrac{\tfrac{51}{199}}{\tfrac{1}{100000}} = \tfrac{51}{199} \times \tfrac{100000}{1} = \tfrac{(51 \times 100000)}{199} = \tfrac{\text{5100000‬}}{199}$
 * $$199$$ in $$\text{5100000?‬}$$ $$25628$$ times, $$(5100000 - 5099972) = 28$$ remainder $$\rightarrow 25628$$


 * $$\tfrac{1}{1000000} \times x = \tfrac{28}{199}$$
 * $$x = \tfrac{\tfrac{28}{199}}{\tfrac{1}{1000000}} = \tfrac{28}{199} \times \tfrac{1000000}{1} = \tfrac{(28 \times 1000000)}{199} = \tfrac{28000000}{199}$$
 * $$199$$ in $$28000000\text{?}$$ $$140703$$ times, $$(28000000 - 27999897) = 103$$ remainder $$\rightarrow 140703$$


 * What have followed is the math behind the algorithm, this is the link to the source code: https://drive.google.com/open?id=1OxHP55gCB0XnoVOJP67Xxbhn5by9zDdr


 * Luigi Baglio 21:05, 22 April 2020 (UTC)


 * Wow! 320 lines in Java! I can see that you worked very hard on this.


 * I am not a Java expert, but I was wondering; On your computer what do you get when you simply divide a double precision variable equal to 1.0 into a double precision variable equal to 199.0 and print out the double precision result?


 * You asked "Instead to remove people additions, you should drive these people where their contents can be published, Wikipedia is big, so if that page seems improper, tell people where and what they can do to get the ideas they exspressed not just on Wikipedia, but on the Internet in general."


 * My answer: This website [ https://www.reddit.com/r/math/ ] allows you to post anything having to do with math. --Guy Macon (talk) 01:18, 23 April 2020 (UTC)


 * Hi, sorry if I am a bit late, but I have been busy: The given code execute the so called division on line 51: String frazioneDoubleStringa = String.format("%0$.15g", (1.0 / n)); n is promoted to double, Eclipse remove the cast if I write it, due to the type promotion rule (I prefer the explicit cast).


 * I am not an expert programmer but from my not professional (I have never worked for companies and so forth) experience I might say that the code you have to write is the amout needed to solve the problem, by keeping in mind that it needs to have some sort of elegance in the eyes of other programmers (the linked document contains an example, not a refined and polished code).


 * After a couple of days I have another hint for you, and for Wikipedia (be a messenger): Thanks for the link, but whould be good if Wikipedia had a sort of polling system that will allow users to vote about a paragraph, an entire page... This way, the contents whould not be removed, but keeped for people to judge, and by selecting the paragraph or the sentence the user should be able to see the amout of likes or dislikes, and at the beginnig of every page there will be two buttons: "Show referenced" and "Show ambigous" and the paragraphs (that are made of complete sentences) will organize (just in time with local resources) accordingly... Moderators have anyway the power to remove contents, but they can choose: It is vandalism, remove it, or: It is something I don't agree, dislike it, and your dislike whould be a bit more weighted by a normal user, that is: 3 user likes to compensate a dislike from you, and keep the paragraph as neutral. So:


 * Referenced view: Referenced contents + Neutral contents + likes;
 * Ambigous view: Referenced contents + Neutral contents + dislikes.
 * Note: Referenced contents can't be voted, the polling system is for the non gods and theirs untrusted, fake, uninformative additions.


 * Of course, you can program Wikipedia to keep always a paragraph with more dislikes than likes, but that whould be unfair... And remember (just in case), that you have to protect a polling system like that from bots.


 * Luigi Baglio 19:54, 27 April 2020 (UTC)