User talk:Greg Glover/sandbox

Firearm boox
v2 vg Ek=½mv2


 * $$i = \frac{2}{ n}$$ $$\sqrt{}$$ $${n}$$


 * $$x=\frac{-b\pm\sqrt{b^2-4ac\ }}{2a}.$$


 * $$i=\frac{2}{n} \sqrt{4n-1}{n}$$


 * $$i=\frac{2}{n} \cdot \frac{\sqrt{4n-1}}{n}$$


 * $$i=\frac{2}{n} \cdot \sqrt{\frac{4n-1}{n}}$$

5 Treatment after 5.1 Level of Care

Math formating

 * $$E_k =\tfrac{1}{2} mv^2 $$

Kinetic energy

 * $$E_t =\tfrac{mv^2}{2g_c} $$
 * $$F = ma\,$$
 * $$E_0 = m c^2 \,$$
 * $$E_t = wz \,$$
 * $$E_t = wz $$


 * $$E_t =\tfrac{mgvt}{2g_c} $$


 * $$E_t =\tfrac{mdFt^2dtt}{t^2mdt^2} $$


 * $$E_t = dF $$

or
 * $$E_t = ft-lb_f $$


 * $$g_c \,$$
 * $$32.174 049 =\tfrac{md}{Ft^2} $$

or
 * $$32.174 049 =\tfrac{lb_m \cdot ft}{lb_f \cdot s^2} $$

or more commonly
 * 32.174 049
 * $$32.174 049 \,$$


 * $$E_t = .5 \cdot mv^2 $$	(in SI units of measure in SI mathematical form)
 * $$E_t =\tfrac{mv^2}{2} $$	(in SI units of measure in English Engineering mathematical form)
 * $$E_t =\tfrac{mv^2}{2g_c} $$	(in English Engineering units of measure in English Engineering  mathematical form)


 * $$hp =\tfrac{ft-lb_f \cdot rpm}{5252} $$

$$Force (lb_f) = m (lb_m) \cdot g (ft/s^2) = \tfrac{ m (slug) \cdot g (ft/s^2)}{g_c (32.174049lb_m ft/lb_f sec^2) } $$


 * $$g_c = 3.28084ft \cdot 2.204623lb_m \cdot 4.4482209lb_f \,$$ -1 $$\cdot (s \,$$ -2$$) = 32.174049ft\cdot lb_m \cdot lb_f\,$$ -1 $$\cdot s\,$$ -2

TKE equations
Substitution: (it yields a totally unrealalistic approximation of free recoil)
 * $$E_{tgu} = E_{tp} \cdot \tfrac {m_p}{m_{gu}} \cdot 1000\,$$

Short form:
 * $$E_{tgu} = 0.5 \cdot [\tfrac {(m_p \cdot v_p) + (m_c \cdot v_c)} { 1000 } ]^2 / m_{gu}$$

Long form:
 * $$v_{gu} = \tfrac {(m_p \cdot v_p) + (m_c \cdot v_c)} {1000} / m_{gu}$$  →   $$E_{tgu} = 0.5 \cdot m_{gu} \cdot v_{gu}^2\,$$

TKE calculation

 * $$E_{tgu} = 0.5 \cdot [\tfrac {(m_p \cdot v_p) + (m_c \cdot v_c)} { 1000 } ]^2 / m_{gu}$$

and with the numaric values in place;
 * $$E_{tgu} = 0.5 \cdot [\tfrac {(9.1 \cdot 823) + (2.75 \cdot 1585)} { 1000 } ]^2 / 4.54 =$$


 * $$E_{tgu} = 0.5 \cdot [\tfrac {(7489.3) + (4358.75)} { 1000 } ]^2 / 4.54 =$$


 * $$E_{tgu} = 0.5 \cdot [\tfrac {11848.05} { 1000 } ]^2 / 4.54 =$$


 * $$E_{tgu} = 0.5 \cdot 11.848^2 / 4.54 = \,$$


 * $$E_{tgu} = 0.5 \cdot 140.367 / 4.54 = \,$$


 * $$E_{tgu} = 70.188 / 4.54 = \,$$


 * $$E_{tgu} = 15.46J = \,$$ of free recoil

Torque

 * $$\boldsymbol \tau = \mathbf{r}\times \mathbf{F}\,\!$$


 * $$\tau = rF\sin \theta\,\!$$

Sign formating

 * $$\boldsymbol \tau = \mathbf{r}+\mathbf{F}\,\!$$
 * $$\boldsymbol \tau = \mathbf{r}-\mathbf{F}\,\!$$
 * $$\boldsymbol \tau = \mathbf{r}\times \mathbf{F}\,\!$$
 * $$\boldsymbol \tau = \mathbf{r}\cdot \mathbf{F}\,\!$$
 * $$\boldsymbol \tau = \mathbf{r}\div \mathbf{F}\,\!$$
 * $$\boldsymbol \tau = \mathbf{r_2}+\mathbf{F}\,\!$$
 * $$\boldsymbol \tau = \mathbf{r^2}+\mathbf{F}\,\!$$
 * $$\boldsymbol \tau \equiv \mathbf{r}+\mathbf{F}\,\!$$

$$\sqrt{4}=2$$
 * This is how you strike through.

This is how you Outdent. Every colon (:) moves the outdent line inboard, one tab.

Pound force



 * 1 pound-force ||= 1pound times the standard acceleration of gravity
 * 1 pound-force ||= 1pound times the standard acceleration of gravity


 * ||= 1 lbm × 32.174 049 ft/s2
 * ||≡ 0.453 592 37 kg × 9.806 65 m/s2
 * ||= 4.448 221 62 N
 * }
 * ||= 4.448 221 62 N
 * }




 * $$ 1lb_f \,$$||$$ = 1lb_m \cdot g \,$$
 * ||$$ =\tfrac{1lb_m \cdot 32.174049 ft}{s^2} $$
 * ||$$ \equiv \tfrac{1kg \cdot 9.80665 m}{s^2} $$
 * ||$$ = 4.44822162 N \,$$
 * }
 * ||$$ \equiv \tfrac{1kg \cdot 9.80665 m}{s^2} $$
 * ||$$ = 4.44822162 N \,$$
 * }




 * 1 pound-force ||= 1 slug·ft/s2
 * }
 * }




 * $$ 1lb_f \,$$||$$ =\tfrac{1slug \cdot 1ft}{s^2} $$
 * }
 * }

Although force and weight can be mathematically equal, they are two distinct quantities:


 * $$F = ma \,$$
 * $$=\tfrac{md}{t^2} $$

and
 * $$w = mg \,$$
 * $$=\tfrac{md}{t^2} $$

The use of “mass” as an interchangeable word with “weight” is really an engineering colloquialism. So within the contexts of Newton's Second Law it is incorrect to say weight is equal to mass or to imply that weight is equivalent to mass:


 * $$w = mg\equiv m $$

outline formating

 * 1) Frame of reference
 * 2) *Merge Inertial reference frame
 * 3) *No formulations
 * 4) *Definition and description of fictitious forces
 * 5) Newton's laws of motion for a particle
 * 6) Euler's laws of motion for rigid bodies and deformable bodies
 * 7) Rectilinear motion (particle) (kinematics and dynamics)
 * 8) *Merge the article Equations of motion.
 * 9) *Including uniform and accelerated rectilinear motion.
 * 10) *Mention momentum, impulse
 * 11) *Inertial and non-inertial reference frames formulations.
 * 12) *Merge parts of content from Mechanics of planar particle motion
 * 13) Curvilinear motion (particle) (Kinematics and dynamics)
 * 14) *Merging Circular motion, Uniform circular motion
 * 15) *Mention Angular momentum
 * 16) *Inertial and non-inertial reference frames formulations.
 * 17) *Merge parts of content from Mechanics of planar particle motion
 * 18) Rigid body mechanics (kinematics and dynamics)
 * 19) *Merging Rigid body, Rotational motion
 * 20) *Mention Angular momentum and linking to its main article.
 * 21) *Inertial and non-inertial reference frames formulations.
 * 22) Centrifugal force
 * 23) *Merge parts of Centrifugal force (rotating reference frame)
 * 24) *Merge Reactive centrifugal force
 * 25) Centripetal force
 * 26) Coriolis force
 * That's how you do an Outline

Task force
Good afternoon Rracecarr,

would be interested in heading up a “Task force” to clean up and standardize all the pages (stubs) that pertain the Foot-Pound-Second System (FPS). The writings and math for pages like Poundal and Foot-poundal is all over the place. I checked out the Pound (mass) page. What are people thinking and for what reason was the Foot-Pound-Second System page redirected to the Pound (mass) page? See here for the proposal.

I would be more than glad to do as much of the work as possible. I think User:Dorminton and User:MarcusMaximus would support this proposal. Greg Glover (talk) 20:43, 11 August 2010 (UTC)

FPS Task force proposal
Objective: to clean up and standardize pages from the Foot-Pound-Second System, its subsystems and units of measure for writing and math.


 * 1) Foot-Pound-Second System (FPS)
 * 2) *Redirected the FPS page away from the Pound (mass) page as a new page that will be the main article.
 * 3) *Write and edit new text for this page.
 * 4) Create subcategory called “Subsystems”
 * 5) *Redirect the English Engineering System page the new FPS page under Subsystems.
 * 6) *Add Gravitational System and Absolute System under Subsystems.
 * 7) *Create a new GravEngAbs box or find the old GravEngAbs box and fix it.
 * 8) *Use Footnotes.
 * 9) "Pound mass"
 * 10) *Create new page for the pound mass(name to be determined); m = F/a.
 * 11) *Write and edit new text for this page specifying Engineering and Absolute subsystems.
 * 12) *Redirect any references of weight to the Pound (mass) page; F = ma or W = mg/gc.
 * 13) Pound-foot (torque)
 * 14) *Redirect or rename this page Foot-pound (torque)
 * 15) *Clean up and standardize.
 * 16) Poundal
 * 17) *Clean up and standardize.
 * 18) Foot-poundal
 * 19) *Clean up and standardize.
 * 20) Pound force
 * 21) *Standardize.
 * 22) Slug
 * 23) *Standardize.

Supported or Unsupported

 * Supported Greg Glover (talk) 20:31, 11 August 2010 (UTC)

Comments
Use the Foot-pound (energy) page as a template.

Richter magnitude examples (2.0 MJ Base)Table Draft
The following table is the final work as of 2:44pm PDT, 21 MAR 11

Richter magnitudes examples
The following table lists the approximate energy equivalents in terms of TNT explosive force – though note that the earthquake energy is released underground rather than overground. Most energy from an earthquake is not transmitted to and through the surface; instead, it dissipates into the crust and other subsurface structures. In contrast, a small atomic bomb blast (see nuclear weapon yield) will not simply cause light shaking of indoor items, since its energy is released above ground.

As stated above the Richter scale is LOG 10 based. Therefore, the Richter scale numbers may appear grossly understated or or overly stated; 8.1 to 8.12 or 9.0 to 9.02 on this table respectively.

That is because LOG 10 is exponential. Specifically it is exponential between the powers of 0 and 1. 10 to the power of 0 equals 1 and  10 to the power of 1  equals 10.

Following, 31.623 to the power of 0 equals 1, 31.623 to the power of 1  equals 31.623 and 31.623 to the power of 2  equals 1000. Therefore, an 8.0 on the Richter scale releases 31.623 times more energy than a 7.0 and a 9.0 on the Richter scale releases 1000 times more energy than a 7.0.


 * Quakes using the more modern magnitude scales will denote their abbreviations: $M_W$ and $M_S$. Those that have no denoted prefix are $M_L$. Please be advised that the magnitude “number” (example 7.0) displayed for those quakes on this table may represent a significantly greater or lesser release in energy then by the correctly given magnitude (example $M_W$).

Good afternoon Glenn L, As I have stated earlier. I can't do logarithms. I see that you can. As I perceive over the last several months the community has adopted my compromise.

Can you go see here and double check the math?