User talk:Karl Stroetmann

Welcome!

Hello,, and welcome to Wikipedia! Thank you for your contributions. I hope you like the place and decide to stay. Here are a few good links for newcomers: I hope you enjoy editing here and being a Wikipedian! Please sign your name on talk pages using four tildes (~&#126;); this will automatically produce your name and the date. If you need help, check out Where to ask a question, ask me on my talk page, or place  on your talk page and someone will show up shortly to answer your questions. Again, welcome! And perhaps you should log in :). Ach so: Willkommen! Lectonar 11:44, 4 October 2005 (UTC)
 * The five pillars of Wikipedia
 * How to edit a page
 * Help pages
 * Tutorial
 * How to write a great article
 * Manual of Style

Hello
I've seen your important contributions for the article Recurrence relation. I'm looking for the general (non-iterative) non-trigonometric expression for the exact trigonometric constants of the form: $$\begin{align}\cos \frac{\pi}{2^n}\end{align}$$, when n is natural (and is not given in advance). Do you know of any such general (non-iterative) non-trigonometric expression? (note that any exponential-expression-over-the-imaginaries is also excluded since it's trivially equivalent to a real-trigonometric expression). Eliko (talk) 08:26, 31 March 2008 (UTC)
 * Let me explain: if we choose n=1 then the term $$\begin{align}\cos \frac{\pi}{2^n}\end{align}$$ becomes "0", which is a simple (non-trigonometric) constant. If we choose n=2 then the term $$\begin{align}\cos \frac{\pi}{2^n}\end{align}$$ becomes $$\begin{align}\frac{1}{\sqrt{2}}\end{align}$$, which is again a non-trigonometric expression. etc. etc. Generally, for every natural n, the term $$\begin{align}\cos \frac{\pi}{2^n}\end{align}$$ becomes a non-trigonometric expression. However, when n is not given in advance, then the very expression $$\begin{align}\cos \frac{\pi}{2^n}\end{align}$$ per se - is a trigonometric expression. I'm looking for the general (non-iterative) non-trigonometric expression equivalent to $$\begin{align}\cos \frac{\pi}{2^n}\end{align}$$, when n is not given in advance. If not for the cosine - then for the sine or the tangent or the cotangent.