User talk:Lauren Cryan

Copyright problems with Deep carbon observatory
Hello. Concerning your contribution, Deep carbon observatory, please note that Wikipedia cannot accept copyrighted text or images obtained from other web sites or printed material, without the permission of the author(s). This article or image appears to be a direct copy from https://dco.gl.ciw.edu/faq, https://dco.gl.ciw.edu/science/deep-carbon-reservoirs-and-fluxes, https://dco.gl.ciw.edu/physicsandchemistry and other subpages. As a copyright violation, Deep carbon observatory appears to qualify for deletion under the speedy deletion criteria. Deep carbon observatory has been tagged for deletion, and may have been deleted by the time you see this message. If you believe that the article or image is not a copyright violation, or if you have permission from the copyright holder to release the content freely under the Creative Commons Attribution/Share-Alike License (CC-BY-SA) then you should do one of the following:


 * If you have permission from the author, leave a message explaining the details at Talk:Deep carbon observatory and send an email with the message to . See Requesting copyright permission for instructions.
 * If a note on the original website states that it is licensed under the CC-BY-SA license, leave a note at Talk:Deep carbon observatory with a link to where we can find that note.
 * If you hold the copyright to the material: send an e-mail from an address associated with the original publication to or a postal message to the Wikimedia Foundation permitting re-use under the CC-BY-SA and GFDL, and note that you have done so on Talk:Deep carbon observatory.

However, for textual content, you may simply consider rewriting the content in your own words. While contributions are appreciated, Wikipedia must require all contributors to understand and comply with its copyright policy. Wikipedia takes copyright concerns very seriously, and persistent violators will be blocked from editing. Thank you. Hairhorn (talk) 03:15, 20 April 2012 (UTC)