User talk:Mckaydjensen

Welcome Mckaydjensen! Now that you've joined Wikipedia, there are users!

Hello, Mckaydjensen. Welcome to Wikipedia and thank you for your contributions! I'm Jax 0677, one of the other editors here, and I hope you decide to stay and help contribute to this amazing repository of knowledge. Alternatively, leave me a message at my talk page or type  here on your talk page, and someone will try to help. Remember to always sign your posts on talk pages. You can do this either by clicking on the button on the edit toolbar or by typing four tildes   at the end of your post. This will automatically insert your signature, a link to this (your talk) page, and a timestamp. The best way to learn about something is to experience it. Explore, learn, contribute, and don't forget to have some fun! To get some practice editing you can use a sandbox. You can [//en.wikipedia.org/w/index.php?title=Special:Mypage/sandbox&action=edit&preload=Template:User_Sandbox/preload create your own private sandbox] for use any time. Perfect for working on bigger projects. Then for easy access in the future, you can put  on your user page. By the way, seeing as you haven't created a user page yet, simply click here to start it.

 Sincerely, Jax 0677 (talk) 21:01, 22 August 2013 (UTC)  [//en.wikipedia.org/w/index.php?title=User_talk:Jax_0677&action=edit&section=new&preload=Template:Welcome_to_Wikipedia/user-talk_preload (Leave me a message)]

Español

Deutsch

Français

Italiano

עברית

Русский

日本語

Polski

فارسی

Recent change to Euler Pentagonal Theorem
Your edits are wrong and I usual do not edit pages, but an error as big as the one you made...I must interject. The good Euler rolled over and sighed on 10/18/2023.

The sign changes for the recurrence relation are (plus,plus,minus,minus,plus,plus,minus,minus,...) or (+,+,-,-,+,+,...). Which is what the previous summation formula correctly demonstrated. You never changed the signs in the expanded formula, thank goodness those are still correct for you to see your error.

The previous and correct old function: (-1)^floor((x+1)2), g(x)=floor((x+1)2). Remotevapephone (talk) 18:11, 20 October 2023 (UTC)


 * Hi, thanks for the comment here. I would just like to clarify:
 * You seem to be saying that the form
 * (-1)^{\lfloor (k + 1) / 2 \rfloor}
 * is correct, which is what I wrote. However, this was reverted by another user, since they index the generalized pentagonal numbers over all positive and negative integers (which I misunderstood with my original edit). Am I understanding you correctly? Mckaydjensen (talk) 18:29, 20 October 2023 (UTC)