User talk:Physicist137

Your submission at Articles for creation: Classical Lie Algebras has been accepted
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Cohn's theorem
The new article titled Cohn's theorem says: An nth-degree polynomial,


 * $$p(z) = p_0 + p_1 z + \cdots + p_n z^n $$

is called self-inversive if


 * $$p(z) = \omega p^*(z),\qquad |\omega|=1,$$

where


 * $$p^*(z)=z^n \bar{p}\left(\frac{1}{z}\right) =\bar{p}_n + \bar{p}_{n-1} z + \cdots + \bar{p}_0 z^n$$

is the reciprocal polynomial associated with $$p(z)$$ and the bar means complex conjugation.

I changed something in it: You had the notation pn referring BOTH to the polynomial itself and to one of the coefficients.

One problem in the present form of that article is that I cannot tell whether the passage above means
 * for EVERY complex number &omega; for which |&omega;| = 1, or
 * for SOME complex number &omega; for which |&omega;| = 1, or
 * something else.

Can you clarify that? Michael Hardy (talk) 20:37, 12 April 2018 (UTC)

Hi Michael Hardy,

The correct is for SOME &omega;. Perhaps a more precise definition would be something like: "p(x) is called self-inversive if there exists a $$\omega \in C: |\omega|=1$$ so that: $$p(z) = \omega p^*(z)$$."