User talk:Qria

In response to your feedback
I have several helpful links on my user page for editing. Feel free to contact me with any questions!

― Ross coolguy  16:08, 30 January 2013 (UTC)

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June 2013
Hello, I'm DVdm. Your recent edit to the page Regular polygon appears to have added incorrect information, so I removed it for now. If you believe the information was correct, please cite a reliable source or discuss your change on the article's talk page. If you think I made a mistake, or if you have any questions, you can leave me a message on my talk page. Thanks. DVdm (talk) 08:50, 10 June 2013 (UTC)

Note - The expression that you provided, $4 (1+\sqrt{2+})$, aka $$4 \left( 1 + \sqrt{ 2 + \sqrt{ 2 \left( 2 + \sqrt{2} \right) } } \right)$$, produces 12.59127551. Cheers - DVdm (talk) 09:00, 10 June 2013 (UTC)

Note - O.t.o.h. using the identity
 * $$\tan\tfrac{1}{2}\theta = \frac{\tan\theta}{1 + \sqrt{1+\tan^2\theta}}$$

it's easy to prove that
 * $$\frac{4}{\cot{\frac{\pi}{16}}} = 4 \left( 1 + \sqrt{2} + \sqrt{ 2 \left(2 +\sqrt{2} \right) } \right)$$

So the correct expression is $4 (1+\sqrt{2}+ \sqrt{2(2+) } )$, which does indeed produce 20.10935797. I'll make the change. I notice you already made the correction. Looks like it was a typo. Cheers - DVdm (talk) 11:50, 10 June 2013 (UTC)