User talk:RobertStar20

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Bacterial growth
If the number of bacteria is increasing exponentially, and each bacterium is reproducing at maximum rate, then the rate of increase can be increasing exponentially, no problems at all. RobertStar20 22:38, 2 Nov 2004 (UTC)


 * If what was meant was the each bacterium separately is reproducing at maximum rate, then the article is very unclear. Moreover, if each bacterium separately is reproducing faster at time t than at any other time, then one would expect slow per capita growth a later times, and therefore the growth rate is not exponential.  In exponential growth, the per capita growth rate remains constant.  If that varies, then growth is not exponential.  Michael Hardy 22:46, 2 Nov 2004 (UTC)


 * If all the individual bacterium are separately reproducing at maximum rate, then the whole colony is at its maximum rate at that point in time, i.e. it is incapable of reproducing any faster. However, I agree that the per capita growth rate at later times will be slower, so it is indeed not technically exponential. Looking at the exponential growth page, maybe the logistic function is what it really is... but isn't this a bit too mathematical perhaps? We need a word which means increasing at an increasing rate, but not necessarily exponentially. As for the graph being incorrect, it's a log y-axis, so an exponential curve will become straight... if only it were actually exponential :-). RobertStar20 23:20, 2 Nov 2004 (UTC)

The Humungous Image Tagging Project
Hi. You've helped with the WikiProject Wiki Syntax, so I thought it worth alerting you to the latest and greatest of Wikipedia fixing project, User:Yann/Untagged Images, which is seeking to put copyright tags on all of the untagged images. There are probably, oh, thirty thousand or so to do (he said, reaching into the air for a large figure). But hey: they're images ... you'll get to see lots of random pretty pictures. That must be better than looking for at at and the the, non? You know you'll love it. best wishes --Tagishsimon (talk)

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