User talk:SamiKaero

In regards to Asshole (disambiguation) page
Hello! I've check the page and there was some pretty moronic vandalism there too. However, If I make a request for a semi-protection, I doubt that they will protect it, because they useally protect it when after consective and numerous bouts of vandalism, just like the parent Asshole article. The one you were taking only had 3 cases of vandal since the month started. In my past protection requests such as Bill Clinton and North Korea, the vandalism was useally one per hour or even more. So in my standards, I would not ask the administrator for page protection for this one, although if you feel that it should need a semi-protection you can go to Requests for page protection. Have a great day! JForget 17:09, 14 October 2006 (UTC)

re fr:Activité chimique
I think that its the scientific jargon that is very much in need in the english article. It appears to my untrained language eye (for french anyway) that the french article describes the mathematical formulae very well as one person said it had good content and it appears that the text is well organised. The English artical has the non mathematical description but if you could translate the most of the french article (from Le potentiel chimique µi) I would happily reorganise the english article because it needs that doing anyway. If there are any jargon terms you can't translate put the french and enlgish guess together and I will easiliy be able to put the correct english equivalent.

Basically the people that wrote the french article appear to have given a very good mathematical description which the english artical is lacking. If you are happy to translate it let me know when its finished and I will check and/or reorganise it. Thank you Ksbrown 09:23, 24 October 2006 (UTC)


 * No problem. Thank you/merci.  Ksbrown 13:09, 24 October 2006 (UTC)


 * Thank you for doing that, it is very helpful. In case it is helpful to you, I have put the copy of the translation that I proof read below so you can see what I changed before I merge it with the rest of the article.  Thanks again, Ksbrown 16:19, 24 October 2006 (UTC)

=Proof read translation= The chemical activity of a species is the influence of the amount of substance of a species on the Helmholtz free energy of a system.

The chemical potential µi of a species i is the partial derivative of the Gibbs free energy of the system compared to the amount of substance ni (number of moles):
 * $$\mu_i = \frac{\partial G}{\partial n_i}$$

This chemical potential depends on the temperature T, pressure p and the activity ai according to the formula :
 * $$\mu_i(T,p) = \mu_i^0(T) + R \cdot T \cdot \ln(a_i)$$

where R is the Ideal Gas Constant and µi0 is the value of µi under standard conditions.

For a gaseuos mixture
The activity is of the form:


 * $$ a_i = \gamma_i \cdot x_i \cdot \frac{p}{p_0} = \frac{f_i}{p_0} $$

where $$\gamma_i$$ is the dimensionless fugacity coefficient (fugacity) of the species i, xi the mole fraction of the species in the gaseous mixture and p the pressure expressed in bar.

The quantity $$f_i$$ has the dimension of pressure and is fugacity of the gas: for a pure Ideal gas, the fugacity coefficient is equal to one.

The value p0 is the standard atmospheric pressure. It is equal to 1 bar and is present to cancel the dimensions of the formula. Thus:
 * $$\mu_i(T,p) = \mu_i^0(T) + R \cdot T \cdot \ln(\gamma_i \cdot x_i \cdot \frac{p}{p_0})$$

For compound in a liquid solution
The activity is of the form:
 * $$ a_i = \gamma_i \frac{C_i}{C_0}$$

Where $$\gamma_i$$ is the coefficient of activity of the species i, Ci is concentration in solution expressed in mol.l-1. The C0 term is equal to 1 mol·l-1 and is present to cancel the dimensions of the formula. Therefore:
 * $$\mu_i(T,p) = \mu_i^0(T) + R \cdot T \cdot \ln(\gamma_i \cdot \frac{C_i}{C_0})$$

It should be noted that in a liquid solution the activity coefficient of a given ion (e.g. Ca2+) isn't measurable because it is experimentaly impossible to independantly measure the electrochemical potential of an ion in solution. Therefore one introduces the notion of 'average activity coefficient'.

Simplifications
The above formulae can be simplified by considerating that: $$a_i = \frac{C_i}{C_0}$$ Therefore, it is approximately equal to its concentration in mol·l-1. $$a_i = \frac{p_i}{p_0}$$ Therefore, it is equal to the partial pressure in bars (compared to a standard pressure of 1 bar).
 * For a chemical solution:
 * the solvent has an activity of unity
 * At a low concentration, the activity of a solute can be approximated to the ratio of its concentration over the standard concentration:
 * For a mix of gas at low pressure, the activity is equal to the ratio of the partial pressure of the gas over the standard pressure:
 * For a solid body, a uniform, single species solid has an activity of unity.

The chemical activities should be used to define the equilibrium constant but in practice often concentrations are used.

Larger than Life
Why is the word "science" in the title of the article Larger than Life (science)? --Metropolitan90 04:57, 26 October 2006 (UTC)

Videora Ipod converter
Hello, SamiKaero, and welcome to Wikipedia. An article you recently created,, has been tagged for speedy deletion because its content is clearly written to promote a company, product, or service. This article may have been deleted by the time you see this message. Please keep in mind that Wikipedia is an encyclopedia, not an advertising service. Thank you. Kyra~(talk) 22:07, 1 November 2006 (UTC)


 * I was not trying to imply that you were related to the Videora company; all I was trying to convey to the admins is that what I took away from the article is that it seemed like an advertisement. However, I did check the link you put in the article's page, and I would like to kindly remind you that when creating new articles, please do not copy them verbatim, as it is a copyright violation. The main reason I tagged the article with the speedy delete tag is because usually speedy deletions have a much quicker turnaround time. I do commend you however, for your contributions to help Wikipedia become even better than it already is, but next time might I suggest rewording the text both so it is not a copyright violation, and so it doesn't seem to be so... ad-like. I wish you a pleasant evening, and happy editing. --Kyra~(talk) 22:47, 1 November 2006 (UTC)

Re: Server (computing) subtile vandalism
I do not know of any adminstrators personally but I have reported the instance in Administrator intervention against vandalism. Kc4 21:04, 4 November 2006 (UTC)

Orphaned non-free image File:Loop Guru.jpg
 Thanks for uploading File:Loop Guru.jpg. The image description page currently specifies that the image is non-free and may only be used on Wikipedia under a claim of fair use. However, the image is currently orphaned, meaning that it is not used in any articles on Wikipedia. If the image was previously in an article, please go to the article and see why it was removed. You may add it back if you think that that will be useful. However, please note that images for which a replacement could be created are not acceptable for use on Wikipedia (see our policy for non-free media).

If you have uploaded other unlicensed media, please check whether they're used in any articles or not. You can find a list of "file" pages you have edited by clicking on the "my contributions" link (it is located at the very top of any Wikipedia page when you are logged in), and then selecting "File" from the dropdown box. Note that any non-free images not used in any articles will be deleted after seven days, as described on criteria for speedy deletion. Thank you. Aspects (talk) 19:18, 7 December 2009 (UTC)