User talk:Saud zahir

Einstein's cosmological constant is calculated as the product of einstein's constant with density of vacuum as Lambda = (8.(pi).G/c^2)x density of vacuum but if we solve einstein formula: (8.(pi).G/c^2). Density of vacuum; where "G" is gravitational constant, "c" is speed of light in vacuum and density of vacuum and replacing it with energy density of universe: U = E/V we know; density of vacuum= U/c^2. U = M.c^2/V ;                E = M.c^2 (mass-energy equation) also              M= c^2.R/G (mass of universe) then "V" volume of universe is ; V = 4.(pi).R^3 substituting it we get; U = c^4/(4.(pi).G.R^2) and putting this in formula; lambda = (8.(pi).G/c^4)x U we get Lambda = 2/R^2 where "R" is radius of universe. And R = c. Age of universe (in seconds). Answer is approximately equal. It means that cosmological constant is actually the inverse of magnitude of expanding space-time of our universe and dark energy is its reverse.