User talk:Thexder

I put p(0) and q(0) back into the indicial polynomial. In this sense, the previous line is misleading -- p(z).z^r=(p_0+p_1.z+p_2.z^2+...).z^r includes terms in z^r, z^(r+1), etc. If we want ONLY the coefficientes in z^r, we restrict ourselves to p_0=p(0) indeed (same thing for q).

March 2009
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