User talk:Warwickk

Hi,

Can someone explain or address, probably a well known pattern, but a new insight to me:

Multiply the number three (3) by any other number, then add the resulting digits and they will ALWAYS add up to either three (3) six(6) or nine (9), and always in that order as the multiplier increases.

3 x 1 = 3 3 x 2 = 6 3 x 3 = 9

3 x 4 = 12, 1 + 2 = 3 3 x 5 = 15, 1 + 5 = 6 3 x 6 = 18, 1 + 8 = 9

3 x 7 = 21, 2 + 1 = 3 ad infinitum. Fascinating stuff! Why is it so?

And finally 3 + 6 + 9 = 18, 1 + 8 = 9. What's going on?

Warwickk (talk) 00:43, 7 June 2009 (UTC)