User talk:Wotnarg

$$\frac{dh}{dt} = -\frac{\sqrt(h)}{5}$$ $$\frac{-5}{dt} = \frac{\sqrt{h}}{dh}$$ $$\int{\frac{dt}{-5}} = \int{\frac{dh}{\sqrt{h}}}$$ $$-1/5*t + C=2\sqrt{h}$$ $$\frac{-1/5*t+C}{2} = \sqrt{h}$$ $$\frac{(-1/5*t+C)^2}{4}=h$$ # Note: in the next step I kill the squared by sqrting both sides $$-1/5*(0)+C/4=17$$ $$C = 17$$

File:Kill dragon.png listed for deletion
An image or media file that you uploaded or altered, File:Kill dragon.png, has been listed at Images and media for deletion. Please see the discussion to see why this is (you may have to search for the title of the image to find its entry), if you are interested in it not being deleted. Skier Dude ( talk ) 07:14, 31 December 2008 (UTC)