User talk:Yumf

Please look carefully at the algorithm:

function query (rectangle r, kd-tree node n) { var axis := n.axis; var median := n.median; if median > r.interval[axis].low then return query(r, n.left); if median < r.interval[axis].high then return query(r, n.right); if median in r.interval[axis] then output n.point; }

rectangle r = [(-1,-1) (1,1)]

Now suppose that the kd-tree only has one node, (0,0), which obviously is in the interval. The code above fails because on the first call:

axis = 0 median = 0 r.interval[axis].low == -1

thus, median > r.interval[axis].low == true

a) If you interpret the return statement as it is usually semantically defined in all programming languages then it checks the left subtree, which is empty, and returns an empty list (i.e. outputs nothing).

b) if you remove the return statements then you are only checking one axis and you can easily find an example in which the wrong point is output.

I think that this algorithm, as it is written, is wrong. If I am wrong in some assumption, please explain.

Thanks, Uranor

Algorithm fixed
Thanks for pointing out the bug. I've updated the page with the fix.

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