Wikipedia:Wikifun/Round 9/Answers/Question 10

a*b=c a=c/b b=c/a. used common sense. Rentastrawberry 04:20, Jun 16, 2005 (UTC)
 * Nope. Next! -- AllyUnion (talk) 07:51, 16 Jun 2005 (UTC)
 * If you haven't figured it out, there is a reason why the words are picked the way they are. -- AllyUnion (talk) 08:46, 16 Jun 2005 (UTC)

Answer
The ratio of a circle used in making pi.-Zxcvbnm 14:24, 18 Jun 2005 (UTC)
 * Sorry. Nice try however, but the answer I am looking for is a cousin of the ingredient used in making simple pastries.  -- AllyUnion (talk) 19:16, 18 Jun 2005 (UTC)

Answer
6H2O + 6CO2 + light → C6H12O6 (glucose) + 6O2 C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

It could be this pair of stabilizing reactions.....--Zxcvbnm 21:52, 21 Jun 2005 (UTC) Used in photosynthesis and celular respiration!!--Zxcvbnm 21:53, 21 Jun 2005 (UTC)


 * You're so close! You're on the border of an answer, but it's not stablizing reactions. -- AllyUnion (talk) 05:40, 22 Jun 2005 (UTC)

Answer!!
Now i get it! The small pastries are THYLAKOIDS!!! They look like pancakes! The formula is 12H2O + 6CO2 + light → glucose + 6O2 + 12H2O used in photosynthesis!!!--Zxcvbnm 16:35, 22 Jun 2005 (UTC)
 * Maybe you should simplify your answer, because that is not what I'm looking for. -- AllyUnion (talk) 08:41, 23 Jun 2005 (UTC)

Answer?
The number of hydrogen atoms on either sidfe of htis reaction catalysed by yeast? Dmn / &#1332;&#1396;&#1398; 1 July 2005 08:59 (UTC)
 * C6H12O6 (glucose) &#8594;2C2H5OH + 2CO2

sugar (hydrogen in glucose synthesis and oxydation)
A basic ingredient for pastry is yeast. From the latter's page (and in yeast (baking)) we learn that in baking (resp. leavening) the carbon dioxide raises the bread, and the ethanol evaporates, and the formula $$C_6H_{12}O_6\to2C_2H_5OH+2CO_2$$, where the sugar consumed by yeast is taken to be glucose.

On the latter's page, we have a picture of the Haworth projection representation of the structure of glucose (α-D-glucopyranose), where each of the 6 carbon atoms has two hydrogen atoms attached to it (one directly, one in form of an OH group (in a special way for the C #5)) (which is not true in the chain form). This could mean the six times two equals 12.

Now if the l.h.s. products are completely "burned" (e.g. in cellular respiration, but also (not always so properly) when any fossile fuel is burned to create energy e.g. also for heating ovens...) then it eventually is broken down to water and carbon dioxyde according to $$C_6H_{12}O_6 + 6O_2 \to 6CO_2 + 6H_2O$$. This could correspond to the 12 divided by 2 (i.e. broken up, in the 2 resulting products) equals 6 (six times two hydrogen atoms). (Additionally, this formula bears several other 2x6 or 6x2 combinations in it, e.g. regarding the O's.)

On the other hand, glucose is created in photosynthesis according to $$6CO_2 + 6H_2O \to C_6H_{12}O_6 + 6O_2 $$. This is the original (first) six times two equals twelve (since this is the creation of the sugar, in contrast to its consumption).

The product "sugar" is also given as basic ("bread") ingredient for baking in yeast (baking)).  &mdash; MFH: Talk 4 July 2005 21:22 (UTC)


 * Far more complex that I asked for, but the answer was glucose and MFH is correct! "This formula is used in making simple pastries" was to imply that the math before it was a simple sugar.  The "6 times 2 is 12. 12 divided by 2 is 6." was to imply the $$C_6H_{12}O_6$$ chemical formula of glucose.  --AllyUnion (talk) 6 July 2005 02:39 (UTC)