2016 Irving Tennis Classic – Doubles

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Doubles
2016 Irving Tennis Classic
Final
ChampionUnited States Nicholas Monroe
Pakistan Aisam-ul-Haq Qureshi
Runner-upAustralia Chris Guccione
Brazil André Sá
Score6–2, 5–7, [10–4]
Events
Singles Doubles
← 2015 · Irving Tennis Classic · 2017 →

Robert Lindstedt and Sergiy Stakhovsky were the defending champions, but didn't participate.

Nicholas Monroe and Aisam-ul-Haq Qureshi won the title, defeating Chris Guccione and André Sá 6–2, 5–7, [10–4].

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 United States N Monroe
Pakistan A-u-H Qureshi
6 6
Italy M Cecchinato
Spain Í Cervantes
6 6 Italy M Cecchinato
Spain Í Cervantes
3 4
India P Raja
South Africa R Roelofse
4 3 1 United States N Monroe
Pakistan A-u-H Qureshi
3 7 [10]
3 United Kingdom C Fleming
United Kingdom N Skupski
79 6 3 United Kingdom C Fleming
United Kingdom N Skupski
6 5 [8]
Germany P Petzschner
Germany M Zverev
67 2 3 United Kingdom C Fleming
United Kingdom N Skupski
6 6
WC United States Nate Eazor
United States Chase Wood
3 6 [10] WC United States N Eazor
United States C Wood
0 1
WC United States Alex Pier
United States T Smyczek
6 2 [7] 1 United States N Monroe
Pakistan A-u-H Qureshi
6 5 [10]
Australia J-P Smith
New Zealand M Venus
610 6 [10] 2 Australia C Guccione
Brazil A Sá
2 7 [4]
Uzbekistan D Istomin
Russia D Tursunov
712 4 [8] Australia J-P Smith
New Zealand M Venus
2 4
Brazil R Dutra Silva
Ecuador G Lapentti
3 4 4 India L Paes
Czech Republic L Rosol
6 6
4 India L Paes
Czech Republic L Rosol
6 6 4 India L Paes
Czech Republic L Rosol
3 2
WC Germany B Becker
The Bahamas M Knowles
3 4 2 Australia C Guccione
Brazil A Sá
6 6
Chinese Taipei J Jung
Germany Jakob Sude
6 6 Chinese Taipei J Jung
Germany J Sude
4 6 [6]
2 Australia C Guccione
Brazil A Sá
6 4 [10]

References[edit]