2019 Hobart International – Doubles

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Doubles
2019 Hobart International
Final
ChampionsChinese Taipei Chan Hao-ching
Chinese Taipei Latisha Chan
Runners-upBelgium Kirsten Flipkens
Sweden Johanna Larsson
Score6–3, 3–6, [10–6]
Events
Singles Doubles
← 2018 · Hobart International · 2020 →

Elise Mertens and Demi Schuurs were the defending champions, but Mertens chose not to participate and Schuurs chose to compete in Sydney instead.

Chan Hao-ching and Latisha Chan won the title, defeating Kirsten Flipkens and Johanna Larsson in the final, 6–3, 3–6, [10–6].

Seeds[edit]

Draw[edit]

Key[edit]

Draw[edit]

First round Quarterfinals Semifinals Final
1 Chinese Taipei H-c Chan
Chinese Taipei L Chan
6 7
  Australia M Adamczak
Australia J Moore
4 5 1 Chinese Taipei H-c Chan
Chinese Taipei L Chan
w/o
  Belarus V Lapko
New Zealand E Routliffe
7 0 [11] Slovenia D Jakupović
United States S Santamaria
  Slovenia D Jakupović
United States S Santamaria
5 6 [13] 1 Chinese Taipei H-c Chan
Chinese Taipei L Chan
6 6
3 Romania M Niculescu
China Z Yang
6 6 3 Romania M Niculescu
China Z Yang
3 4
  China X Jiang
China S Zhang
4 2 3 Romania M Niculescu
China Z Yang
6 6
  Romania R Olaru
Kazakhstan G Voskoboeva
6 6 Romania R Olaru
Kazakhstan G Voskoboeva
1 4
  Russia A Panova
Germany L Siegemund
4 3 1 Chinese Taipei H-c Chan
Chinese Taipei L Chan
6 3 [10]
WC Australia Z Hives
Australia E Perez
3 7 [7] 4 Belgium K Flipkens
Sweden J Larsson
3 6 [6]
  Croatia D Jurak
United States D Krawczyk
6 5 [10] Croatia D Jurak
United States D Krawczyk
1 4
  Spain L Arruabarrena
Spain S Sorribes Tormo
4 5 4 Belgium K Flipkens
Sweden J Larsson
6 6
4 Belgium K Flipkens
Sweden J Larsson
6 7 4 Belgium K Flipkens
Sweden J Larsson
7 6
WC Australia A Bai
Australia A Poulos
3 2 Russia A Potapova
Ukraine D Yastremska
5 4
  Russia A Potapova
Ukraine D Yastremska
6 6 Russia A Potapova
Ukraine D Yastremska
6 77
  United States K Christian
Chile A Guarachi
6 3 [8] 2 Romania I-C Begu
Romania M Buzărnescu
4 63
2 Romania I-C Begu
Romania M Buzărnescu
1 6 [10]

References[edit]