Talk:William Ros, 1st Baron Ros

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

Cites needed[edit]

According to The Complete Peerage, Vol. XI, pp. 96-7, the barony of Ros of Hemsley was created by writ with William de Ros (who is numbered in this Wikipedia article as the 2nd Baron). In Magna Carta Ancestry, Vol. III, p. 448, Richardson also uses this numbering. It thus seems likely that all the Wikipedia articles on the Barons de Ros should be renumbered. Comments? NinaGreen (talk) 19:39, 6 December 2012 (UTC)[reply]

To add to what I wrote above on 6 December, The Complete Peerage, Vol. XI, p. 95, states that on 24 December 1264 Robert de Ros was summoned to Simon de Montfort's Parliament in London, but according to a footnote on that page:

In 1616 the Barony was allowed precedence from this writ, a decision adopted by the Lords in 1806 (Round, Peerage and Pedigree, vol. i, pp. 249-50); but these writs, issued by Simon in the King's name, are no longer regarded as valid for the creation of peerages.

It thus seems necessary to renumber the baronies in this article, as suggested above, particularly since, in addition to the reliable sources cited above, the online source, Cracroft's Peerage, cited in this article, also states that William was the first baron. NinaGreen (talk) 01:26, 29 December 2012 (UTC)[reply]

It's ok with me as long as you cross your T's and dot your i's. However, you need to add your sources to the article itself. Please add these sources as IN LINE cites to this article. -- Ssilvers (talk) 23:33, 30 December 2012 (UTC)[reply]

Good progress, although this article is still a mess. Thanks for all your hard work. I see you added the Richardson ref, but you have not used it in line. -- Ssilvers (talk) 00:29, 31 December 2012 (UTC)[reply]
I've now added the Richardson citation inline, and have made a start on improving the article by adding details of family, with links to other related articles, and citations. NinaGreen (talk) 04:33, 31 December 2012 (UTC)[reply]