1948 Iowa Senate election

The 1948 Iowa State Senate elections took place as part of the biennial 1948 United States elections. Iowa voters elected state senators in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the year 1948 is provided by the Iowa General Assembly here.

The primary election on June 3, 1948 determined which candidates appeared on the November 5, 1948 general election ballot.

Following the previous election, Republicans had control of the Iowa state Senate with 46 seats to Democrats' 4 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 22 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1948 general election with the balance of power shifting to Republicans holding 43 seats and Democrats having 7 seats (a net gain of 3 seats for Democrats).

Summary of Results

 * Note: The 21 holdover Senators not up for re-election are not listed on this table.

Source:

Detailed Results

 * NOTE: The 21 districts that did not hold elections in 1948 are not listed here.
 * Note: If a district does not list a primary, then that district did not have a competitive primary (i.e., there may have only been one candidate file for that district).