1988 CONCACAF Champions' Cup

The 1988 CONCACAF Champions' Cup was the 24th. edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region and was played from 11 March till 21 December 1988.

The teams were split in 2 zones, North/Central America and Caribbean, (as North and Central America sections combined to qualify one team for the final), each one qualifying two teams to the final tournament.

Hondurean club Olimpia beat Trinidarian side Defence Force 4–0 on aggregate to become champions, thus achieving their second CONCACAF trophy.

Preliminary round

 * Morelia, Cruz Azul and Alajuelense advance to the First Round.

North American Zone

 * Morelia and Cruz Azul advance to Fourth Round.

Central American Zone
Played in Guatemala City


 * Alajuelense and Marathon advance to the Third Round.

Central American Zone
Played in Tegucigalpa


 * Olimpia and Aurora advance to the Third Round.

Central American Zone
Played in Tegucigalpa


 * Alajuelense and Olimpia advance to the Fourth Round.

North/Central American Zone

 * Morelia disqualified after refusing to play the series.*
 * Olimpia and Alajuelense advance to the CONCACAF Semi-Finals.

First round
Matches and results unknown: Zenith 🇸🇷 Robinhood  Sion Hill  Cardinals


 * All clubs in BOLD advance to the second round.

Second round
Matches and results unknown: La Gauloise 🇯🇲 Seba United 🇬🇫 Sport Guyanais


 * Further results for the following round are unknown; Robin Hood and Defence Force advance to the CONCACAF Semi-Finals.

Semi-finals

 * Olimpia and Defence Force advance to the CONCACAF Final.

Second leg

 * Olimpia won 4–0 on points and also 4–0 on aggregate.