Talk:Wilson–Cowan model

$$S(\bar{N})=\int_{\frac{\theta}{\bar{N}(t)}}^{\infty}C(w)dw$$

Where does this integral come from? I cannot find it in the original paper and I doubt its correctness. Example: If the excitation threshold $$\theta$$ is twice the average excitation $$\bar{N}$$, then this would integrate over all neurons that have $$\omega\geq2$$ afferent synapses. However, in order for a neuron to belong to the excited subpopulation $$S(\bar{N})$$, it should have at least twice the average no. of afferent nerve fibers, not just two afferent synapses (or more). — Preceding unsigned comment added by LoSchizzatore (talk • contribs) 12:53, 19 July 2018 (UTC)