User:Arperry

User page = sandbox? Here, the answer is Yes.

Maths
$$ d = \frac{1+min(\frac{S}{P},2)}{2}P$$

$$ d' = \frac{2A_2}{A_1+1} d \ | \ A_1 > A_2$$

$$ %Cr = \frac{A_1}{A_1 + CC}$$

$$ m' = m + \frac{I}{5}$$