1992 United States presidential election in Maryland

The 1992 United States presidential election in Maryland took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

Maryland was won by Governor Bill Clinton (D-Arkansas) with 49.80% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 35.62%. Businessman Ross Perot (I-Texas) finished in third, with 14.18% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush. In this election, Maryland voted 8.62% to the left of the nation at-large.

Although Clinton won only four of Maryland's 23 counties (and the independent city of Baltimore), the high raw vote totals from these heavily populated jurisdictions exceeded Bush's victories in largely rural and exurban counties. Maryland was of only three states, along with New York and Clinton's native Arkansas (and Washington DC), where Clinton exceeded Bush and Perot's combined vote total, albeit by an extremely slim margin of 63 votes. This is also the most recent election when the Democratic candidate failed to win a majority of the state's popular vote.

This marks the last election as of 2020 in which both Charles County and Dorchester County voted for the same candidate. In 1996, Dorchester County would be flipped to the Democratic column by a plurality for the first time since 1960 and vote for every ensuing Republican, whilst Charles County would become one of only two counties in the entire nation to flip from supporting Bob Dole to support Al Gore, and never vote Republican again, due to its increasing African-American population.

Counties that flipped from Republican to Democratic

 * Baltimore
 * Howard