1992 United States presidential election in Mississippi

The 1992 United States presidential election in Mississippi took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

Mississippi was won by incumbent President George H. W. Bush (R-Texas) with 49.68% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.77%. Businessman Ross Perot (I-Texas) finished in third, with 8.72% of the popular vote. Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.

Despite the fact that Clinton was from neighbouring Arkansas, the state remained reliably Republican as the party held two senate seats. While Clinton did manage to win a few other Southern States, Mississippi provided Bush with his highest vote percentage in the nation, which was the closest he came to winning an absolute majority in a state. (However, it was only his sixth-best state in margin of victory.) It was Ross Perot's weakest state, and the only one where he failed to win more than 10% of the vote. He only did worse in the District of Columbia. , this is the last election in which Hinds County voted for a Republican presidential candidate and the last election in which Tishomingo County voted for a Democratic presidential candidate.

67% of white voters supported Bush, while 22% supported Clinton. 11% supported Perot.

Counties that flipped from Republican to Democratic

 * Adams
 * Alcorn
 * Amite
 * Chickasaw
 * Jasper
 * Kemper
 * Leflore
 * Panola
 * Pike
 * Tishomingo
 * Washington
 * Yalobusha