Bornological space

In mathematics, particularly in functional analysis, a bornological space is a type of space which, in some sense, possesses the minimum amount of structure needed to address questions of boundedness of sets and linear maps, in the same way that a topological space possesses the minimum amount of structure needed to address questions of continuity. Bornological spaces are distinguished by the property that a linear map from a bornological space into any locally convex spaces is continuous if and only if it is a bounded linear operator.

Bornological spaces were first studied by George Mackey. The name was coined by Bourbaki after, the French word for "bounded".

Bornologies and bounded maps
A  on a set $$X$$ is a collection $$\mathcal{B}$$ of subsets of $$X$$ that satisfy all the following conditions:  $$\mathcal{B}$$ covers $$X;$$ that is, $$X = \cup \mathcal{B}$$; $$\mathcal{B}$$ is stable under inclusions; that is, if $$B \in \mathcal{B}$$ and $$A \subseteq B,$$ then $$A \in \mathcal{B}$$; $$\mathcal{B}$$ is stable under finite unions; that is, if $$B_1, \ldots, B_n \in \mathcal{B}$$ then $$B_1 \cup \cdots \cup B_n \in \mathcal{B}$$;  Elements of the collection $$\mathcal{B}$$ are called ' or simply ' if $$\mathcal{B}$$ is understood. The pair $$(X, \mathcal{B})$$ is called a ' or a '.

A ' or ' of a bornology $$\mathcal{B}$$ is a subset $$\mathcal{B}_0$$ of $$\mathcal{B}$$ such that each element of $$\mathcal{B}$$ is a subset of some element of $$\mathcal{B}_0.$$ Given a collection $$\mathcal{S}$$ of subsets of $$X,$$ the smallest bornology containing $$\mathcal{S}$$ is called the 

If $$(X, \mathcal{B})$$ and $$(Y, \mathcal{C})$$ are bornological sets then their  on $$X \times Y$$ is the bornology having as a base the collection of all sets of the form $$B \times C,$$ where $$B \in \mathcal{B}$$ and $$C \in \mathcal{C}.$$ A subset of $$X \times Y$$ is bounded in the product bornology if and only if its image under the canonical projections onto $$X$$ and $$Y$$ are both bounded.

Bounded maps
If $$(X, \mathcal{B})$$ and $$(Y, \mathcal{C})$$ are bornological sets then a function $$f : X \to Y$$ is said to be a ' or a ' (with respect to these bornologies) if it maps $$\mathcal{B}$$-bounded subsets of $$X$$ to $$\mathcal{C}$$-bounded subsets of $$Y;$$ that is, if $$f(\mathcal{B}) \subseteq \mathcal{C}.$$ If in addition $$f$$ is a bijection and $$f^{-1}$$ is also bounded then $$f$$ is called a .

Vector bornologies
Let $$X$$ be a vector space over a field $$\mathbb{K}$$ where $$\mathbb{K}$$ has a bornology $$\mathcal{B}_{\mathbb{K}}.$$ A bornology $$\mathcal{B}$$ on $$X$$ is called a  if it is stable under vector addition, scalar multiplication, and the formation of balanced hulls (i.e. if the sum of two bounded sets is bounded, etc.).

If $$X$$ is a topological vector space (TVS) and $$\mathcal{B}$$ is a bornology on $$X,$$ then the following are equivalent:  $$\mathcal{B}$$ is a vector bornology; Finite sums and balanced hulls of $$\mathcal{B}$$-bounded sets are $$\mathcal{B}$$-bounded; The scalar multiplication map $$\mathbb{K} \times X \to X$$ defined by $$(s, x) \mapsto sx$$ and the addition map $$X \times X \to X$$ defined by $$(x, y) \mapsto x + y,$$ are both bounded when their domains carry their product bornologies (i.e. they map bounded subsets to bounded subsets). 

A vector bornology $$\mathcal{B}$$ is called a if it is stable under the formation of convex hulls (i.e. the convex hull of a bounded set is bounded) then $$\mathcal{B}.$$ And a vector bornology $$\mathcal{B}$$ is called if the only bounded vector subspace of $$X$$ is the 0-dimensional trivial space $$\{ 0 \}.$$

Usually, $$\mathbb{K}$$ is either the real or complex numbers, in which case a vector bornology $$\mathcal{B}$$ on $$X$$ will be called a  if $$\mathcal{B}$$ has a base consisting of convex sets.

Bornivorous subsets
A subset $$A$$ of $$X$$ is called ' and a ' if it absorbs every bounded set.

In a vector bornology, $$A$$ is bornivorous if it absorbs every bounded balanced set and in a convex vector bornology $$A$$ is bornivorous if it absorbs every bounded disk.

Two TVS topologies on the same vector space have that same bounded subsets if and only if they have the same bornivores.

Every bornivorous subset of a locally convex metrizable topological vector space is a neighborhood of the origin.

Mackey convergence
A sequence $$x_\bull = (x_i)_{i=1}^\infty$$ in a TVS $$X$$ is said to be if there exists a sequence of positive real numbers $$r_\bull = (r_i)_{i=1}^\infty$$ diverging to $$\infty$$ such that $$(r_i x_i)_{i=1}^\infty$$ converges to $$0$$ in $$X.$$

Bornology of a topological vector space
Every topological vector space $$X,$$ at least on a non discrete valued field gives a bornology on $$X$$ by defining a subset $$B \subseteq X$$ to be bounded (or von-Neumann bounded), if and only if for all open sets $$U \subseteq X$$ containing zero there exists a $$r > 0$$ with $$B \subseteq rU.$$ If $$X$$ is a locally convex topological vector space then $$B \subseteq X$$ is bounded if and only if all continuous semi-norms on $$X$$ are bounded on $$B.$$

The set of all bounded subsets of a topological vector space $$X$$ is called ' or ' of $$X.$$

If $$X$$ is a locally convex topological vector space, then an absorbing disk $$D$$ in $$X$$ is bornivorous (resp. infrabornivorous) if and only if its Minkowski functional is locally bounded (resp. infrabounded).

Induced topology
If $$\mathcal{B}$$ is a convex vector bornology on a vector space $$X,$$ then the collection $$\mathcal{N}_{\mathcal{B}}(0)$$ of all convex balanced subsets of $$X$$ that are bornivorous forms a neighborhood basis at the origin for a locally convex topology on $$X$$ called the .

If $$(X, \tau)$$ is a TVS then the  is the vector space $$X$$ endowed with the locally convex topology induced by the von Neumann bornology of $$(X, \tau).$$

$$

Quasi-bornological spaces
Quasi-bornological spaces where introduced by S. Iyahen in 1968.

A topological vector space (TVS) $$(X, \tau)$$ with a continuous dual $$X^{\prime}$$ is called a  if any of the following equivalent conditions holds:

<ol> <li>Every bounded linear operator from $$X$$ into another TVS is continuous.</li> <li>Every bounded linear operator from $$X$$ into a complete metrizable TVS is continuous.</li> <li>Every knot in a bornivorous string is a neighborhood of the origin.</li> </ol>

Every pseudometrizable TVS is quasi-bornological. A TVS $$(X, \tau)$$ in which every bornivorous set is a neighborhood of the origin is a quasi-bornological space. If $$X$$ is a quasi-bornological TVS then the finest locally convex topology on $$X$$ that is coarser than $$\tau$$ makes $$X$$ into a locally convex bornological space.

Bornological space
In functional analysis, a locally convex topological vector space is a bornological space if its topology can be recovered from its bornology in a natural way.

Every locally convex quasi-bornological space is bornological but there exist bornological spaces that are quasi-bornological.

A topological vector space (TVS) $$(X, \tau)$$ with a continuous dual $$X^{\prime}$$ is called a  if it is locally convex and any of the following equivalent conditions holds:

<ol> <li>Every convex, balanced, and bornivorous set in $$X$$ is a neighborhood of zero.</li> <li>Every bounded linear operator from $$X$$ into a locally convex TVS is continuous. <li>Every bounded linear operator from $$X$$ into a seminormed space is continuous.</li> <li>Every bounded linear operator from $$X$$ into a Banach space is continuous.</li> </ol>
 * Recall that a linear map is bounded if and only if it maps any sequence converging to $$0$$ in the domain to a bounded subset of the codomain. In particular, any linear map that is sequentially continuous at the origin is bounded.</li>

If $$X$$ is a Hausdorff locally convex space then we may add to this list: <li>The locally convex topology induced by the von Neumann bornology on $$X$$ is the same as $$\tau,$$ $$X$$'s given topology.</li> <li>Every bounded seminorm on $$X$$ is continuous.</li> <li>Any other Hausdorff locally convex topological vector space topology on $$X$$ that has the same (von Neumann) bornology as $$(X, \tau)$$ is necessarily coarser than $$\tau.$$</li> <li>$$X$$ is the inductive limit of normed spaces.</li> <li>$$X$$ is the inductive limit of the normed spaces $$X_D$$ as $$D$$ varies over the closed and bounded disks of $$X$$ (or as $$D$$ varies over the bounded disks of $$X$$).</li> <li>$$X$$ carries the Mackey topology $$\tau(X, X^{\prime})$$ and all bounded linear functionals on $$X$$ are continuous.</li> <li> $$X$$ has both of the following properties: where a subset $$A$$ of $$X$$ is called  if every sequence converging to $$0$$ eventually belongs to $$A.$$ </li> </ol>
 * $$X$$ is ' or ', which means that every convex sequentially open subset of $$X$$ is open,
 * $$X$$ is ' or ', which means that every convex and bornivorous subset of $$X$$ is sequentially open.

Every sequentially continuous linear operator from a locally convex bornological space into a locally convex TVS is continuous, where recall that a linear operator is sequentially continuous if and only if it is sequentially continuous at the origin. Thus for linear maps from a bornological space into a locally convex space, continuity is equivalent to sequential continuity at the origin. More generally, we even have the following:

<ul> <li>Any linear map $$F : X \to Y$$ from a locally convex bornological space into a locally convex space $$Y$$ that maps null sequences in $$X$$ to bounded subsets of $$Y$$ is necessarily continuous.</li> </ul>

Sufficient conditions
$$

As a consequent of the Mackey–Ulam theorem, "for all practical purposes, the product of bornological spaces is bornological."

The following topological vector spaces are all bornological: <ul> <li>Any locally convex pseudometrizable TVS is bornological. <li>Any strict inductive limit of bornological spaces, in particular any strict LF-space, is bornological. <li>A countable product of locally convex bornological spaces is bornological.</li> <li>Quotients of Hausdorff locally convex bornological spaces are bornological.</li> <li>The direct sum and inductive limit of Hausdorff locally convex bornological spaces is bornological.</li> <li>Fréchet Montel spaces have bornological strong duals.</li> <li>The strong dual of every reflexive Fréchet space is bornological.</li> <li>If the strong dual of a metrizable locally convex space is separable, then it is bornological.</li> <li>A vector subspace of a Hausdorff locally convex bornological space $$X$$ that has finite codimension in $$X$$ is bornological.</li> <li>The finest locally convex topology on a vector space is bornological.</li> </ul>
 * Thus every normed space and Fréchet space is bornological.</li>
 * This shows that there are bornological spaces that are not metrizable.</li>


 * Counterexamples

There exists a bornological LB-space whose strong bidual is bornological.

A closed vector subspace of a locally convex bornological space is not necessarily bornological. There exists a closed vector subspace of a locally convex bornological space that is complete (and so sequentially complete) but neither barrelled nor bornological.

Bornological spaces need not be barrelled and barrelled spaces need not be bornological. Because every locally convex ultrabornological space is barrelled, it follows that a bornological space is not necessarily ultrabornological.

Properties
<ul> <li>The strong dual space of a locally convex bornological space is complete.</li> <li>Every locally convex bornological space is infrabarrelled.</li> <li>Every Hausdorff sequentially complete bornological TVS is ultrabornological. <li>The finite product of locally convex ultrabornological spaces is ultrabornological.</li> <li>Every Hausdorff bornological space is quasi-barrelled.</li> <li>Given a bornological space $$X$$ with continuous dual $$X^{\prime},$$ the topology of $$X$$ coincides with the Mackey topology $$\tau(X, X^{\prime}).$$ <li>Every quasi-complete (i.e. all closed and bounded subsets are complete) bornological space is barrelled. There exist, however, bornological spaces that are not barrelled.</li> <li>Every bornological space is the inductive limit of normed spaces (and Banach spaces if the space is also quasi-complete).</li> <li> Let $$X$$ be a metrizable locally convex space with continuous dual $$X^{\prime}.$$ Then the following are equivalent: <ol> <li>$$\beta(X^{\prime}, X)$$ is bornological.</li> <li>$$\beta(X^{\prime}, X)$$ is quasi-barrelled.</li> <li>$$\beta(X^{\prime}, X)$$ is barrelled.</li> <li>$$X$$ is a distinguished space.</li> </ol> </li> <li>If $$L : X \to Y$$ is a linear map between locally convex spaces and if $$X$$ is bornological, then the following are equivalent: <ol> <li>$$L : X \to Y$$ is continuous.</li> <li>$$L : X \to Y$$ is sequentially continuous.</li> <li>For every set $$B \subseteq X$$ that's bounded in $$X,$$ $$L(B)$$ is bounded.</li> <li>If $$x_{\bull} = (x_i)_{i=1}^\infty$$ is a null sequence in $$X$$ then $$L \circ x_\bull = (L(x_i))_{i=1}^\infty$$ is a null sequence in $$Y.$$</li> <li>If $$x_\bull = (x_i)_{i=1}^\infty$$ is a Mackey convergent null sequence in $$X$$ then $$L \circ x_\bull = (L(x_i))_{i=1}^\infty $$ is a bounded subset of $$Y.$$</li> </ol> </li> <li>Suppose that $$X$$ and $$Y$$ are locally convex TVSs and that the space of continuous linear maps $$L_b(X; Y)$$ is endowed with the topology of uniform convergence on bounded subsets of $$X.$$ If $$X$$ is a bornological space and if $$Y$$ is complete then $$L_b(X; Y)$$ is a complete TVS. </ul>
 * Thus every complete Hausdorff bornological space is ultrabornological.
 * In particular, every Fréchet space is ultrabornological.</li>
 * In particular, bornological spaces are Mackey spaces.</li>
 * In particular, the strong dual of a locally convex bornological space is complete. However, it need not be bornological.</li>


 * Subsets

<ul> <li>In a locally convex bornological space, every convex bornivorous set $$B$$ is a neighborhood of $$0$$ ($$B$$ is required to be a disk).</li> <li>Every bornivorous subset of a locally convex metrizable topological vector space is a neighborhood of the origin.</li> <li>Closed vector subspaces of bornological space need not be bornological.</li> </ul>

Ultrabornological spaces
A disk in a topological vector space $$X$$ is called  if it absorbs all Banach disks.

If $$X$$ is locally convex and Hausdorff, then a disk is infrabornivorous if and only if it absorbs all compact disks.

A locally convex space is called  if any of the following equivalent conditions hold: <ol> <li>Every infrabornivorous disk is a neighborhood of the origin.</li> <li>$$X$$ is the inductive limit of the spaces $$X_D$$ as $$D$$ varies over all compact disks in $$X.$$</li> <li>A seminorm on $$X$$ that is bounded on each Banach disk is necessarily continuous.</li> <li>For every locally convex space $$Y$$ and every linear map $$u : X \to Y,$$ if $$u$$ is bounded on each Banach disk then $$u$$ is continuous.</li> <li>For every Banach space $$Y$$ and every linear map $$u : X \to Y,$$ if $$u$$ is bounded on each Banach disk then $$u$$ is continuous.</li> </ol>

Properties
The finite product of ultrabornological spaces is ultrabornological. Inductive limits of ultrabornological spaces are ultrabornological.